3+(1/3)x^2-2x=0

Solution for 3+(1/3)x^2-2x=0 equation:

3+(1/3)x^2-2x=0


Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)x^2-2x+3=0

We add all the numbers together, and all the variables

-2x+(+1/3)x^2+3=0

We multiply all the terms by the denominator


-2x*3)x^2+(+3*3)x^2+1=0

We add all the numbers together, and all the variables

-2x*3)x^2+9x^2+1=0

Wy multiply elements

-6x^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-12}=0$